2[p-(3p+18)+12]=2(p+6)

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Solution for 2[p-(3p+18)+12]=2(p+6) equation:


Simplifying
2[p + -1(3p + 18) + 12] = 2(p + 6)

Reorder the terms:
2[p + -1(18 + 3p) + 12] = 2(p + 6)
2[p + (18 * -1 + 3p * -1) + 12] = 2(p + 6)
2[p + (-18 + -3p) + 12] = 2(p + 6)

Reorder the terms:
2[-18 + 12 + p + -3p] = 2(p + 6)

Combine like terms: -18 + 12 = -6
2[-6 + p + -3p] = 2(p + 6)

Combine like terms: p + -3p = -2p
2[-6 + -2p] = 2(p + 6)
[-6 * 2 + -2p * 2] = 2(p + 6)
[-12 + -4p] = 2(p + 6)

Reorder the terms:
-12 + -4p = 2(6 + p)
-12 + -4p = (6 * 2 + p * 2)
-12 + -4p = (12 + 2p)

Solving
-12 + -4p = 12 + 2p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-2p' to each side of the equation.
-12 + -4p + -2p = 12 + 2p + -2p

Combine like terms: -4p + -2p = -6p
-12 + -6p = 12 + 2p + -2p

Combine like terms: 2p + -2p = 0
-12 + -6p = 12 + 0
-12 + -6p = 12

Add '12' to each side of the equation.
-12 + 12 + -6p = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -6p = 12 + 12
-6p = 12 + 12

Combine like terms: 12 + 12 = 24
-6p = 24

Divide each side by '-6'.
p = -4

Simplifying
p = -4

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